Assertion: In the Lyman series,the ratio of m | vedclass

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(A) The Rydberg formula is given by $\frac{1}{\lambda} = R \left( \frac{1}{n_{1}^{2}} - \frac{1}{n_{2}^{2}} \right)$.For the Lyman series,the ground s

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If both Assertion and Reason are correct and the Reason is a correct explanation of the Assertion.

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(A) The Rydberg formula is given by $\frac{1}{\lambda} = R \left( \frac{1}{n_{1}^{2}} - \frac{1}{n_{2}^{2}} \right)$.For the Lyman series,the ground state is $n_{1} = 1$.For the minimum wavelength (shortest wavelength),$n_{2} = \infty$:$\frac{1}{\lambda_{min}} = R \left( \frac{1}{1^{2}} - \frac{1}{\infty^{2}} \right) = R \implies \lambda_{min} = \frac{1}{R}$.For the maximum wavelength (longest wavelength),$n_{2} = 2$:$\frac{1}{\lambda_{max}} = R \left( \frac{1}{1^{2}} - \frac{1}{2^{2}} \right) = R \left( 1 - \frac{1}{4} \right) = \frac{3R}{4} \implies \lambda_{max} = \frac{4}{3R}$.The ratio of minimum to maximum wavelength is $\frac{\lambda_{min}}{\lambda_{max}} = \frac{1/R}{4/3R} = \frac{3}{4}$.Both the Assertion and Reason are correct,and the Reason correctly explains the origin of the Lyman series transitions.

Assertion: In the Lyman series,the ratio of minimum and maximum wavelength is $\frac{3}{4}$.
Reason: The Lyman series constitutes spectral lines corresponding to transitions from higher energy levels to the ground state of the hydrogen atom.

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Assertion: In the Lyman series,the ratio of minimum and maximum wavelength is $\frac{3}{4}$.Reason: The Lyman series constitutes spectral lines corresponding to transitions from higher energy levels to the ground state of the hydrogen atom.